Detonations with One-Step Chemistry
A popular model is a reaction mechanism just of one exothermic reaction
%MATHMODE{ A\longrightarrow B }%
with the energy release
%MATHMODE{ h_A^0-h_B^0=:\Delta h^0>0 }%
and the reaction rate
%MATHMODE{ k^f(T) = k \exp (-E_A/{\cal R}T)\;. }%
The production rates for this model read
%MATHMODE{ \dot \omega_A = - k \rho_A \exp (-E_A/{\cal R}T) \quad {\rm and} \qquad \dot \omega_B = -\dot \omega_A\;. }%
Further, the species
A and
B are assumed to be
calorically perfect gases with
%MATHMODE{ \gamma=\gamma_A=\gamma_B \;. }%
In this case, the hydrodynamic pressure can be evaluated directly from the conserved quantities by
%MATHMODE{ p = (\gamma-1)(\rho e - \rho (1-Z)h_A^0-\rho Z h_B^0)\;. }%
Under the additional assumption
%MATHMODE{ h_B^0=0 }%
the energy release is usually denoted by
%MATHMODE{ q_0:=\Delta h^0=h_A^0 }%
and the equation of state
%MATHMODE{ p = (\gamma-1)(\rho e - \rho (1-Z)\, q_0) }%
is derived.
Subsections
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RalfDeiterding - 14 Dec 2004